2.1.1有理数の算術演算、問題2.1 – SICP(計算機プログラムの構造と解釈)その25
2008年11月29日
2.1.1 有理数の算術演算
cons
(construct)、car
(Contents of Address part of Register)、cdr
(Contents of Decrement part of Register)によって対(pair)を作り有理数を表現する。
(define x (cons 1 2))
(car x)
1
(cdr x)
2
(define (add-rat x y)
(make-rat (+ (* (numer x) (denom y))
(* (numer y) (denom x)))
(* (denom x) (denom y))))
(define (sub-rat x y)
(make-rat (- (* (numer x) (denom y))
(* (numer y) (denom x)))
(* (denom x) (denom y))))
(define (mul-rat x y)
(make-rat (* (numer x) (numer y))
(* (denom x) (denom y))))
(define (div-rat x y)
(make-rat (* (numer x) (denom y))
(* (denom x) (numer y))))
(define (equal-rat? x y)
(= (* (numer x) (denom y))
(* (numer y) (denom x))))
(define (make-rat n d) (cons n d))
(define (numer x) (car x))
(define (denom x) (cdr x))
(define (print-rat x)
(display (numer x))
(display "/")
(display (denom x))
(newline))
(define one-half (make-rat 1 2))
(print-rat one-half)
gosh> 1/2
(define one-third (make-rat 1 3))
(print-rat one-third)
gosh> 1/3
(print-rat (add-rat one-half one-third))
gosh> 5/6
(print-rat (sub-rat one-half one-third))
gosh> 1/6
(print-rat (mul-rat one-half one-third))
gosh> 1/6
(print-rat (div-rat one-half one-third))
gosh> 3/2
(print-rat (add-rat one-third one-third))
gosh> 6/9
問題2.1
正負両方の引数を扱う改良版 make-rat
(define (make-rat n d)
(let ((g (gcd (abs n) (abs d))))
(let ((g-n (/ n g))
(g-d (/ d g)))
(if (< d 0)
(cons (- g-n) (- g-d))
(cons g-n g-d)))))
(define one-third (make-rat 1 -3))
(print-rat (add-rat one-third one-third))
gosh> -2/3
(print-rat (mul-rat one-third one-third))
gosh> 1/9
(print-rat (mul-rat one-half one-third))
gosh> -1/6
計算機プログラムの構造と解釈
posted with amazlet at 08.11.07
ジェラルド・ジェイ サスマン ジュリー サスマン ハロルド エイブルソン
ピアソンエデュケーション
売り上げランキング: 6542
ピアソンエデュケーション
売り上げランキング: 6542